(Solution) - The rate law for the reaction of HO with tert butyl -(2025 Original AI-Free Solution)

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The rate law for the reaction of HO- with tert-butyl bromide to form an elimination product in 75% ethanol 25% water at 30 °C is the sum of the rate laws for the E2 and E1 reactions:
rate = 7.1 × 10-5[tert-butyl bromide][HO-] + 1.5 × 10-5[tert-butyl bromide]
What percentage of the reaction takes place by the E2 pathway when these conditions exist?
a. [HO-] = 5.0 M
b. [HO-] = 0.0025 M