(Solution) - The electric field intensity E z due to a ring of -(2025 Original AI-Free Solution)

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The electric field intensity, E(z), due to a ring of radius R at any point z along the axis of the
ring is given by:

where ? is the charge density, ?0 = 8.85 × I0-12 is the electric constant, and R is the radius of the ring. Consider the case where ? = 1.7 × 10-7 C/m and R = 6 cm.
(a) Determine E(z) at z = 0, 2, 4, 6, 8, and 10 cm.
(b) Determine the distance z where E is maximum. Do it by creating a vector z with elements ranging from 2 cm to 6 cm and spacing of 0.01 cm. Calculate E for each value of z and then find the maximum E and associated z with MATLAB's built-in function max.