(Solution) - a Taking h 12Z eV in the quantum mechanical energy loss -(2025 Original AI-Free Solution)

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(a) Taking h(?) = 12Z eV in the quantum-mechanical energy-loss formula, calculate the rate of energy loss (in MeV/cm) in air at NTP, aluminum, copper, and lead for a proton and a mu meson, each with kinetic energies of 10,100,1000 MeV.
(b) Convert your results to energy loss in units of MeV ? (cm2/g) and compare the values obtained in different materials. Explain why all the energy losses in MeV-(cm2/g) are within a factor of 2 of each other, whereas the values in MeV/cm differ greatly.